Subject

    Quantitative Aptitude

    Topic

    Pipes & Cistern

    A can do a job in 24 days, B in 9 days and C in 12 days. B and C together start the work but leave after 3 days. How much time was taken A to complete remaining work ?

    ক)
    7 days
    খ)
    9 days
    গ)
    10 days
    ঘ)
    12 days

    Explanation

    Solution: B+C can do in 1 day = 19+112=4+336=736\frac{1}{9} + \frac{1}{{12}} = \frac{{4 + 3}}{{36}} = \frac{7}{{36}} B+C can do in 3 days = 7×336=712\frac{{7 \times 3}}{{36}} = \frac{7}{{12}} Remaining part =  1−712=5121 - \frac{7}{{12}} = \frac{5}{{12}} 1 part is done by A = 24 day 5/12 part is done by A =  24×51224 \times \frac{5}{{12}} =  10 days

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