Subject
Quantitative Aptitude
Topic
Miscellaneous
A mixture contains wine and water in the ratio 3 : 2 and another mixture contains them in the ratio 4 : 5. How many litres of the latter must be mixed with 3 litres of the former so that the resulting mixture may contain equal quantities of wine and water?
A mixture contains wine and water in the ratio 3 : 2 and another mixture contains them in the ratio 4 : 5. How many litres of the latter must be mixed with 3 litres of the former so that the resulting mixture may contain equal quantities of wine and water?
ক)
\(5\frac{2}{5}\) litreখ)
\(5\frac{2}{3}\) litreগ)
\(4\frac{1}{2}\) itreঘ)
\(3\frac{3}{4}\) litreঙ)
None of theseExplanation
Solution A ⇒ 3 litres solution (3 : 2 ∷ wine : water) Solution B ⇒ x litres solution (4 : 5 ∷ wine : water) According to question Solution A is mixed with Solution B and forms ⇒ (3 + x) litres solution (1 : 1 ∷ wine : water) For Wine Wine in Sol A + Wine in Sol B = Wine in net Solution (3/5) × 3 + (4/9) × x = 1/2 × (3+x) ⇒ (4x/9) – (x/2) = (3/2) - (9/5) ⇒ (8x/18) – (9x/18) = (15/10) – (18/10) ⇒ 3/10 = x / 18 ⇒ x = 5.4 litres = litreRelated questions
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