Subject
Quantitative Aptitude
Topic
Mensuration
The adjacent sides of a parallelogram are 12cm and 14cm and angle between them is 60°. What is the area of the parallelogram?
The adjacent sides of a parallelogram are 12cm and 14cm and angle between them is 60°. What is the area of the parallelogram?
ক)
\(168\sqrt 3\ c{m^2}\)খ)
\(84\sqrt 3\ c{m^2}\)গ)
\(2/2\ c{m^2}\)ঘ)
\(324\sqrt 2\)ঙ)
None of theseExplanation
We know that :- Formula :- (i) Area of a parallelogram = base × height (ii) Area of a parallelogram = product of two adjacent sides × sine of angle between them From formula (ii) we get – ⇒ Area of the required parallelogram = 12 × 14 × sin 60° cm 2 \eqalign{ & = 168 \times {{\sqrt 3 } \over 2}\ c{m^2} \cr & = 84\sqrt 3\ c{m^2} \cr}Related questions
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