Subject

    গণিত

    Topic

    Algebra

    Express r1^2 + r2^2 for a quadratic ax^2 + bx + c = 0 in terms of coefficients.

    ক)
    (−b/a)^2 − 2(c/a)
    খ)
    (b/a)^2 + 2(c/a)
    গ)
    2(−b/a) − (c/a)
    ঘ)
    (−b/a)^2 + 2(c/a)

    Explanation

    Start with Viète's relations for the quadratic ax^2 + bx + c = 0: r1 + r2 = −b/a, r1 r2 = c/a. Compute r12+r22=(r1+r2)2−2r1r2=( ⁣−ba ⁣)2−2⋅ca=b2a2−2ca=b2−2aca2. r_1^2 + r_2^2 = (r_1 + r_2)^2 - 2r_1r_2 = \Big(\!-\frac{b}{a}\!\Big)^2 - 2\cdot\frac{c}{a} = \frac{b^2}{a^2} - \frac{2c}{a} = \frac{b^2 - 2ac}{a^2}. Thus the correct choice is Option 1: (−ba)2−2ca.\displaystyle \Big(-\frac{b}{a}\Big)^2 - 2\frac{c}{a}. (Option 4, which has a plus sign, is incorrect.)

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