Subject

    গণিত

    Topic

    Algebra

    Real-coefficient polynomial with roots 2, 1 ± i; write the monic cubic.

    ক)
    x3− 4x2+ 6x − 4
    খ)
    x3− 4x2+ 5x − 2
    গ)
    x3− 3x2+ 4x − 2
    ঘ)
    x3− 2x2+ 2x − 2

    Explanation

    We are given roots 2,  1+i,  1−i2,\;1+i,\;1-i and asked for the monic cubic polynomial with real coefficients. Since complex roots come in conjugate pairs for real-coefficient polynomials, the quadratic factor from 1±i1\pm i is (x−(1+i))(x−(1−i))=((x−1)−i)((x−1)+i)=(x−1)2+1=x2−2x+2. (x-(1+i))(x-(1-i))=((x-1)-i)((x-1)+i)=(x-1)^2+1 = x^2-2x+2. Multiplying by the linear factor for the root 22 gives the cubic: (x−2)(x2−2x+2). (x-2)(x^2-2x+2). Expand: (x−2)(x2−2x+2)=x3−2x2+2x−2x2+4x−4=x3−4x2+6x−4. \begin{aligned} (x-2)(x^2-2x+2) &= x^3-2x^2+2x -2x^2+4x-4\\ &= x^3-4x^2+6x-4. \end{aligned} So the monic cubic is x3−4x2+6x−4x^3-4x^2+6x-4, which matches Option 1.

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